What amount of bromine will be required to convert $2 \mathrm{~g}$ of phenol into $2,4,6$ -tribromophenol?
- $4.0$
- $6.0$
- $10.22$
- $20.44$
Solution

Thus $94 \mathrm{~g}$ of phenol require $\mathrm{Br}_{2}=480 \mathrm{~g}$
$2 \mathrm{~g}$ of phenol require $\mathrm{Br}_{2}=\frac{480}{94} \times 2=10.22 \mathrm{~g}$ .
Asked in: JEE-TOPICTESTS-CHEMISTRY
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