What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol? (Given molar…

What amount of bromine will be required to convert 2 g of phenol into 2,4,6-tribromophenol? (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{Br}$ are $12,1,16,80$ respectively)
  1. 20.44 g
  2. 4.0 g
  3. 6.0 g
  4. 10.22 g

Solution


$\begin{aligned} & \text { Moles of phenol }=\frac{2}{94}=0.021 \\ & \therefore \text { Moles of bromine }=0.021 \times 3=0.064 \\ & \therefore \text { Mass of bromine }=0.064 \times 160=10.22 \mathrm{~g}\end{aligned}$

Asked in: JEE Main 2025 (23 Jan Shift 1)

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