We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’ and ‘ C ’ with concentration 0 . 1 M , 0 . 01 M and 0 . 001 M , respectively. The value of van t ’ Haft factor i for these solutions will be in the order.

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Aicharya · Accepted Answer

It is because the extent or degree of dissociation increases with increase in dilution of a solution. $0.001 M N a C l$ solution $' C'$ is most diluted as compared to the other two $N a C l$ solutions. The vant Hoff factor (i) depends on extent of dilution.This confirms answer at (i) $i_{A} < i_{B} < i_{C}$

We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’ and ‘ C ’ with concentration 0 . 1 M , 0 .…

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