Water rises to height $2 \cdot 2 \mathrm{~cm}$ in glass capillary tube. The height to which same water rises in another capillary having $\frac{1}{4}$ area of cross-section is

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Aicharya · Accepted Answer

$\mathrm{h}_{1}=2.2 \mathrm{~cm}, \mathrm{~h}_{2}=?$ $\mathrm{~h}_{1} \mathrm{r}_{1}=\mathrm{h}_{2} \mathrm{r}_{2}$ $\mathrm{~h}_{1} \sqrt{\mathrm{A}_{1}}=\mathrm{h}_{2} \sqrt{\mathrm{A}_{2}}$ $\mathrm{~h}_{2}=\frac{\mathrm{h}_{1} \sqrt{\mathrm{A}_{1}}}{\sqrt{\mathrm{A}_{2}}}=2.2 	imes 2=4.4 \mathrm{~cm}$

Water rises to height $2 \cdot 2 \mathrm{~cm}$ in glass capillary tube. The height to which same water rises…

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