Water rises in a capillary tube of radius ' $r$ ' upto height ' $h$ ' The mass of water in the capillary is ' $m$ ' The mass of water will rise in a capillary of radius will $\frac{r}{4}$ be

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Aicharya · Accepted Answer

The height of water column in a capillary tube is given by $\mathrm{h}=\frac{2 \mathrm{~T} \cos 	heta}{\mathrm{perg}}$ From eqs. (i) and (ii), we get $\begin{aligned} & m \propto r^2 	imes \frac{1}{r} \ & m \propto r \ & \Rightarrow \frac{m^{\prime}}{m}=\frac{\frac{r}{4}}{r} \Rightarrow m^{\prime}=\frac{m}{4}\end{aligned}$ :

Water rises in a capillary tube of radius ' $r$ ' upto height ' $h$ ' The mass of water in the capillary is…

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