Water is flowing through a horizontal pipe of non-uniform cross-section. In the region of narrowest part…

Water is flowing through a horizontal pipe of non-uniform cross-section. In the region of narrowest part inside the pipe, the water will have
  1. maximum velocity and minimum pressure.
  2. both the pressure and velocity maximum.
  3. both the pressure and velocity minimum.
  4. maximum pressure and minimum velocity.

Solution

By equation of continuity $\mathrm{A}_{1} \mathrm{~V}_{1}=\mathrm{A}_{2} \mathrm{~V}_{2}$ Hence if area of cross-section decreases, the velocity increases. By Bernoulli's equation $p+\frac{1}{2} \rho V^{2}=\text { constant }$ $\therefore$ if $V$ increase pressure decreases. Hence in the narrowest part, velocity is maximum and pressure is minimum.

Asked in: MHT CET 2020 (13 Oct Shift 2)

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