Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipe
Water is flowing through a horizontal pipe in stream line flow. At the narrowest part of the pipe
velocity is maximum and pressure is minimum
pressure is maximum and velocity is minimum
both pressure and velocity are minimum
both pressure and velocity are maximum
Solution
Using equation of continuity,
$\mathrm{A}_1 \mathrm{~V}_1=\mathrm{A}_2 \mathrm{~V}_2$
In streamlined flow, as the product of $\mathrm{Av}$ is a constant, the velocity at the narrowest part will be maximum.
By using Bernoulli's principle,
$\mathrm{P}+\frac{1}{2} \rho v^2+\rho g h=\text { Constant }$
We see that $\rho g h$ is constant because the pipe is horizontal.
As velocity increases, for the equation to remain constant, $\mathrm{P}$ has to decrease.
$\therefore \quad$ Velocity will be maximum and pressure is minimum
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