Water is flowing in streamline manner in a horizontal pipe. If the pressure at a point where cross-sectional…
- 2500 Pa
- 2000 Pa
- 1000 Pa
- 500 Pa
Solution
Applying Bernoulli's theorem at point 1 and 2 , $\begin{aligned} & \mathrm{P}_1=\frac{1}{2} \delta \mathrm{v}_1^2=\mathrm{P}_2+\frac{1}{2} \delta \mathrm{v}_2^2 \\ & \Rightarrow 2000+\frac{1}{2} \times 10^3 \times 1^2=\mathrm{P}_2+\frac{1}{2} \times 10^3 \times 2^2 \\ & \therefore \quad \mathrm{P}_2=2000+\frac{1}{2} \times 10^3\left(1^2-2^2\right) \\ & =500 \mathrm{~Pa} \end{aligned}$
Asked in: AP EAMCET 2024 (22 May Shift 1)
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