Water in a cuboidal tank of base $80$ cm $\times 60$ cm rises by $5$ cm when an iron piece is fully…

Water in a cuboidal tank of base $80$ cm $\times 60$ cm rises by $5$ cm when an iron piece is fully submerged in it. The volume of the iron piece is:
  1. $24000 \text{ cm}^{3}$
  2. $2400 \text{ cm}^{3}$
  3. $240 \text{ cm}^{3}$
  4. $48000 \text{ cm}^{3}$

Solution

Volume of displaced water $=$ volume of iron piece $= 80 \times 60 \times 5 = 24000 \text{ cm}^{3}$.

Asked in: IMO

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