Water flows in a horizontal pipe whose one end is closed with a valve. The reading of the pressure gauge…
- $P_1-P_2$
- $\left(P_1-P_2\right)^4$
- $\left(\mathrm{P}_1-\mathrm{P}_2\right)^2$
- $\sqrt{\mathrm{P}_1-\mathrm{P}_2}$
Solution

Using Bernoulli's theorem
$\begin{aligned}
& P_1-P_2=\frac{1}{2} \rho v^2 \\ & v \propto \sqrt{P_1-P_2}
\end{aligned}$
Asked in: JEE Main 2025 (23 Jan Shift 2)
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