Physics › Mechanical Properties of Fluids › Viscosity
Water flows from a tap of diameter 1.5 cm with $7.5 \times 10^{-5} \mathrm{~m}^3 \mathrm{~s}^{-1}$…
Water flows from a tap of diameter 1.5 cm with $7.5 \times 10^{-5} \mathrm{~m}^3 \mathrm{~s}^{-1}$ Coefficient of Viscosity of water is $10^{-3}$ Pas. The flow is
Turbulent with Reynolds number less than 6000 Steady flow with Reynolds number less than 2000 Turbulent with Reynolds number greater than 6000 Steady flow with Reynolds number more than 6000 Solution
$\mathrm{D}=1.5 \mathrm{~cm}, \mathrm{Q}=7.5 \times 10^{-5} \mathrm{~m}^3 / \mathrm{s}, \eta=10^{-3} \mathrm{Pas}$
$Q=A v \Rightarrow \frac{\pi}{4} D^2 v \Rightarrow v=\frac{4 Q}{\pi D^2}$
$\therefore$ Reynold's number,
$\begin{aligned}
& R_e=\frac{\delta^{v D}}{\eta}=\frac{\delta\left(\frac{4 Q}{\pi D^2}\right) \cdot D}{\eta}=\frac{4 \delta^Q}{\eta \pi D} \\
& =\frac{4 \times 10^3 \times 7.5 \times 10^{-5}}{10^{-3} \times 3.14 \times 1.5 \times 10^{-2}} \\
& =6369.4\gt4000
\end{aligned}$
$\therefore$ Flow is turbulent.
Asked in: AP EAMCET 2024 (23 May Shift 1)
Practice more Mechanical Properties of Fluids questions on Aicharya