Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool.
$\left(\right.$ Take $g=10 \mathrm{~m} / \mathrm{s}^2$, specific heat of water $\left.=4200 \mathrm{~J} /(\mathrm{kg} \mathrm{K})\right)$

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{mgh}=\mathrm{ms} \Delta \mathrm{T} \ & \Delta \mathrm{T}=\frac{\mathrm{gh}}{\mathrm{s}}=\frac{10 	imes 200}{4200} \mathrm{~K}=\frac{10}{21} \mathrm{~K}\end{aligned}$

Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no…

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