Water drops are falling from a nozzle of a shower onto the floor from a height of 9 . 8   m . The drops…

Water drops are falling from a nozzle of a shower onto the floor from a height of 9.8 m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.
  1. 2.94 m
  2. 4.18 m
  3. 2.45 m
  4. 7.35 m

Solution

For first drop.

h=12g(2n)2

For 2nd  drop

h'=12g(n)2

hh'=41

h'=h4=9.84

so height of 2nd  drop

H=h-h'=9.8-9.84=34×9.8=7.35 m

Asked in: JEE Main 2021 (27 Aug Shift 2)

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