Volume of a cylindrical tank with $r=7$ m, $h=4$ m (use $\pi=22/7$) =
Volume of a cylindrical tank with $r=7$ m, $h=4$ m (use $\pi=22/7$) =
- $616$ m³
- $176$ m³
- $308$ m³
- $1232$ m³
Solution
$(22/7)\cdot49\cdot4=616$.
Asked in: MH-SSC-9
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