Volume of a cuboid is $x^{3} + 6x^{2} + 11x + 6$ cubic units. If two of its dimensions are $(x+1)$ and…
Volume of a cuboid is $x^{3} + 6x^{2} + 11x + 6$ cubic units. If two of its dimensions are $(x+1)$ and $(x+2)$, the third dimension is
- $x + 3$
- $x + 6$
- $x - 3$
- $x + 11$
Solution
Check: $(x+1)(x+2)(x+3) = (x^{2}+3x+2)(x+3) = x^{3}+6x^{2}+11x+6$. So third dimension $= x+3$.
Asked in: IMO
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