Volume occupied by one molecule of water (density $\left.=1 \mathrm{~g} \mathrm{~cm}^{-3}\right)$ is

Volume occupied by one molecule of water (density $\left.=1 \mathrm{~g} \mathrm{~cm}^{-3}\right)$ is
  1. $5.5 \times 10^{-23} \mathrm{~cm}^3$
  2. $9.0 \times 10^{-23} \mathrm{~cm}^3$
  3. $6.023 \times 10^{-23} \mathrm{~cm}^3$
  4. $3.0 \times 10^{-23} \mathrm{~cm}^3$

Solution

Volume of 1 molecule of $\mathrm{H}_2 \mathrm{O}=\frac{18 \mathrm{~g}}{6.02 \times 10^{23} \times 1 \mathrm{~g} / \mathrm{cc}}$ $\cong 3.0 \times 10^{-23} \mathrm{~cm}^3$

Asked in: NEET 2008 (Mains)

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