Voltage rating of a parallel plate capacitor is $500 \mathrm{~V}$. Its dielectric can withstand a maximum electric field of $10^{6} \mathrm{~V} \mathrm{~m}^{-1}$. The plate area is $10^{-4} \mathrm{~m}^{2}$. What is the dielectric constant if the capacitance is $15 \mathrm{pF}$ ? (given…

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Voltage rating of a parallel plate capacitor is $500 \mathrm{~V}$. Its dielectric can withstand a maximum electric field of $10^{6} \mathrm{~V} \mathrm{~m}^{-1}$. The plate area is $10^{-4} \mathrm{~m}^{2}$. What is the dielectric constant if the capacitance is $15 \mathrm{pF}$ ? (given $\epsilon 0=8.86 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$)

Aicharya · Accepted Answer

$\begin{array}{l} \mathrm{C}=\mathrm{K} \varepsilon_{0} \mathrm{~A} / \mathrm{d} \text { and } \mathrm{V}=\mathrm{Ed} \ \text { Or } \mathrm{K}=\mathrm{CV} / \varepsilon_{0} \mathrm{AE}_{\max } \ \mathrm{K}=\left(15 \times 10^{-12} \times 500\right) /\left(8.86 \times 10^{-12} \times 10^{-4} \times 10^{6}\right)=8.5 \end{array}$

Voltage rating of a parallel plate capacitor is \(500 \mathrm{~V}\). Its dielectric can withstand a maximum…

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