Vertex angle of isosceles triangle is $40^{\circ}$. Each base angle is

Vertex angle of isosceles triangle is $40^{\circ}$. Each base angle is
  1. $70^{\circ}$
  2. $40^{\circ}$
  3. $140^{\circ}$
  4. $50^{\circ}$

Solution

$\dfrac{180-40}{2} = 70^{\circ}$.

Asked in: MH-SSC-9

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