Velocity $(v)$ versus displacement $(x)$ plot of a body moving along a straight line is as shown in the graph. The corresponding plot of acceleration (a) as a function of displacement $(x)$ is

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Aicharya · Accepted Answer

The given graph $ v=K x $

$ \frac{d v}{d t}=K \cdot v $ (from the Eq. (i)) $ \text { and } \quad \begin{aligned} \frac{d v}{d t} & =K \cdot(K x)=K^2 x \\ a & =K^2 x \\ v & =-K x+v_0 \\ \frac{d v}{d t} & =-K \cdot v=-K\left(-K x+v_0\right) \\ a & =K^2 x-K v_0 \end{aligned} $ and So, according to the Eq. (ii).

Velocity $(v)$ versus displacement $(x)$ plot of a body moving along a straight line is as shown in the…

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