Velocity of sound in open-ended tube is $330\text{ ms}^{-1}$, the frequency of tuning fork is $1.1\text{…

Velocity of sound in open-ended tube is $330\text{ ms}^{-1}$, the frequency of tuning fork is $1.1\text{ kHz}$ and the length of tube $= 30\text{ cm}$. In which harmonic will it oscillate?
  1. 2nd
  2. 3rd
  3. 4th
  4. 5th

Solution

Let the tube will oscillate in $n\text{th}$ harmonic. Then, $n \left(\frac{v}{2l}\right) = 1.1 \times 10^3$ $\therefore n = \frac{2.2 \times 10^3 \times l}{v} = \frac{2.2 \times 10^3 \times 0.3}{330} = 2$

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