Vectors a i ^ + b j ^ + k ^ and 2 i ^ - 3 j ^ + 4 k ^ are perpendicular to each other when 3 a + 2 b = 7 ,…

Vectors ai^+bj^+k^ and 2i^-3j^+4k^ are perpendicular to each other when 3a+2b=7, the ratio of a to b is x2. The value of x is _____.

Solution

Dot product of two perpendicular vectors will be zero. Therefore,

ai^+bj^+k^·2i^-3j^+4k^=0

2a-3b+4=0   ...Eq(1)

As given in the question,

3a+2b=7   ...Eq(2)

From both equations, we get a=1 & b=2

Then, 

ab=x2x=2ab=2×12

  x=1

Asked in: JEE Main 2023 (24 Jan Shift 1)

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