Vapour pressure of solvent 'A' is $0.90 \mathrm{~atm}$, when a non volatile solute is added, vapour pressure drops to $0.60 \mathrm{~atm}$, what is mole fraction of $\mathrm{A}$ in solution?

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Aicharya · Accepted Answer

$\begin{array}{l} \frac{P_{0}-P}{P_{0}}=x_{2} \ \frac{0.9-0.6}{0.9}=0.333 \end{array}$ Now, $x_{1}+x_{2}=1$ $	herefore \quad x_{1}=1-x_{2}=1-0.333=0.667$

Vapour pressure of solvent 'A' is $0.90 \mathrm{~atm}$, when a non volatile solute is added, vapour pressure…

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