Vapour pressure of a pure solvent is 550 mm of Hg . By addition of a non volatile solute it decreases to 510 mm of Hg . Calculate the mole fraction of solute in solution.

Question

Aicharya · Accepted Answer

$\begin{aligned} & \frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=x_2 \ 	herefore \quad & \frac{550-510}{550}=0.072\end{aligned}$

Vapour pressure of a pure solvent is 550 mm of Hg . By addition of a non volatile solute it decreases to 510…

Solution