Using the given $\mathrm{P}-\mathrm{V}$ diagram, the work done by an ideal gas along the path ABCD is :
Using the given $\mathrm{P}-\mathrm{V}$ diagram, the work done by an ideal gas along the path ABCD is :
Using the given $\mathrm{P}-\mathrm{V}$ diagram, the work done by an ideal gas along the path ABCD is :
- $3 \mathrm{P}_0 \mathrm{~V}_0$
- $-4 \mathrm{P}_0 \mathrm{~V}_0$
- $-3 \mathrm{P}_0 \mathrm{~V}_0$
- $4 \mathrm{P}_0 \mathrm{~V}_0$
Solution
Area under graph will be magnitude of graph and being counterclockwise graph it would be negative
$\begin{aligned}
& \text { Area }=2 P_0 \times V_0+P_0 V_0=3 P_0 V_0 \\ & \mathrm{~W}=-3 P_0 V_0
\end{aligned}$
Asked in: JEE Main 2025 (23 Jan Shift 2)