Using Kirchhoff's law, find the current flowing through the given circuit.
Using Kirchhoff's law, find the current flowing through the given circuit.
$7 \cdot 5 \mathrm{~A}$
$5 \mathrm{~A}$
$10 A$
$3 A$
Solution
The two cells are opposing each other. The net emf in the circuit is $(200-10)=190 \mathrm{~V}$. $\therefore$ current $I=\frac{V}{R}=\frac{190}{38}=5 A$
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