Using Einstein's photoelectric equation, the graph between the K-E.(E) of photoelectrons emitted and the…

Using Einstein's photoelectric equation, the graph between the K-E.(E) of photoelectrons emitted and the frequency of incident radiation ( $\mathrm{v}$ ) is shown correctly in figure (A) (B) (C) (D)
  1. (C)
  2. (A)
  3. (D)
  4. (B)

Solution

Kinetic energy of photo electron emitted K. E = hv $-\phi$ where $v$ is the frequency of incident radiation and $\phi$ is the work function of the metal. Thus graph of $\mathrm{K} . \mathrm{E}$ Vs $v$ is a straight line with slope equal to h , having an intercept on negative $y$-axis which is equal to the work function ( $\phi$ ) of metal. As h is a constant, thus the slope is same for all metals and independent of the intensity of the incident radiation.
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Asked in: MHT CET 2020 (14 Oct Shift 1)

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