Under similar conditions enthalpy of freezing is exactly opposite to
Under similar conditions enthalpy of freezing is exactly opposite to
enthalpy of fusion
enthalpy of vaporization
enthalpy of solution
enthalpy of atomization
Solution
For the reaction, $\mathrm{H}_2 \mathrm{O}_{(\mathrm{s})} [\text { freezing }]{\text { fusion }} \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}$
Under similar conditions of $0^{\circ} \mathrm{C}$ and 1 atm pressure, $\Delta_{\mathrm{fus}} \mathrm{H}$ is $+6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}$, whereas $\Delta_{\text {free }} \mathrm{H}$ is $-6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Thus, enthalpy of freezing is exactly opposite to enthalpy of fusion.