Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecule changes from τ 1 to τ 2 . If C P C v = γ for this gas then a good estimate for τ 2 τ 1 is given by

Question

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time between the gas molecule changes from &#964; 1 to &#964; 2 . If C P C v = &#947; for this gas then a good estimate for &#964; 2 &#964; 1 is given by

Aicharya · Accepted Answer

Relaxation time &#964; &#8733; V T And T &#8733; 1 V &#947; - 1 &#964; &#8733; V 1 + &#947; - 1 2 &#964; &#8733; V 1 + &#947; 2 &#964; f &#964; i = 2 V V &#947; + 1 2 &#964; f &#964; i = 2 &#947; + 1 2

Under an adiabatic process, the volume of an ideal gas gets doubled. Consequently, the mean collision time…

Solution