
Two wooden blocks of masses $M$ and $m$ are placed on a smooth horizontal surface as shown in figure. If a…

- $(M+m) g \tan \beta$
- $g \tan \beta$
- $m g \cos \beta$
- $(M+m) g \operatorname{cosec} \beta$
Solution

$\begin{aligned} & \text { Force }=\text { Mass } \times \text { Acceleration } \\ & \therefore \quad P=(M+m) a \\ & m a \cos \beta=m g \sin \beta \\ & \Rightarrow \quad a=g \frac{\sin \beta}{\cos \beta} \\ & =g \tan \beta \\ & \therefore \quad P=(M+m) g \tan \beta \\ & \end{aligned}$
Asked in: AP EAMCET 2013