Two wires of same material of radius ' $r$ ' and ' $2 r$ ' respectively are welded together end to end. The…

Two wires of same material of radius ' $r$ ' and ' $2 r$ ' respectively are welded together end to end. The combination is then used as a sonometer wire under tension ' $\mathrm{T}$ '. The joint is kept midway between the two bridges. The ratio of the number of loops in the wires with that the joint is a node is
  1. $1: 5$
  2. $1: 2$
  3. $1: 4$
  4. $1: 3$

Solution

Frequency of vibration will be same for both the segments. If $\mathrm{p}_1$ and $\mathrm{p}_2$ are the number of loops for the wires of radius $r$ and $2 r$ then we have $\begin{aligned} & \mathrm{n}=\frac{\mathrm{p}_1}{2 \ell} \sqrt{\frac{\mathrm{T}}{\pi \mathrm{r}^2 \rho}}=\frac{\mathrm{p}_2}{4 \ell} \sqrt{\frac{\mathrm{T}}{\pi(2 \mathrm{r})^2 \rho}} \\ & \therefore \frac{\mathrm{p}_1}{\mathrm{p}_2}=\frac{1}{2} \end{aligned}$

Asked in: MHT CET 2021 (20 Sep Shift 2)

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