Two waves of frequency \(f\) and amplitude \(a\) superimpose with each other. The total intensity is…
Two waves of frequency \(f\) and amplitude \(a\) superimpose with each other. The total intensity is directly proportional to
\(a\)
\(2 a\)
\(2 a^2\)
\(4 a^2\)
Solution
When two waves of same frequency \(f\) and having same amplitude \(a\) superimpose, then resultant amplitude,
\(A=a+a=2 a\)
Total intensity \(I\) of resultant wave is directly proportional to square of amplitude.
\(\text {i.e., } \quad I \propto A^2 \Rightarrow I \propto(2 a)^2 \Rightarrow I \propto 4 a^2\)