Two voltameters one of copper and another of silver, are joined in parallel. When a total charge $q$ flows…

Two voltameters one of copper and another of silver, are joined in parallel. When a total charge $q$ flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are $z_1$ and $z_2$ respectively the charge which flows through the silver voltameter is
  1. $\frac{q}{1+\frac{z_1}{z_2}}$
  2. $\frac{q}{1+\frac{z_2}{z_1}}$
  3. $\mathrm{q} \frac{z_1}{z_2}$
  4. $\mathrm{q} \frac{z_2}{z_1}$

Solution

$q_1 Z_1=q_2 Z_2$ $q=q_1+q_2$ $\therefore q_2=\frac{q}{1+\frac{Z_2}{Z_1}}$

Asked in: JEE Main 2005

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