Two vertical poles A B = 15   m and C D = 10   m are standing apart on a horizontal ground with…

Two vertical poles AB=15 m and CD=10 m  are standing apart on a horizontal ground with points A and C on the ground. If P is the point of intersection of BC and AD, then the height of P (in m ) above the line AC is :
  1. 20/3
  2. 5
  3. 10/3
  4. 6

Solution

ΔAQP~ΔACD

⇒ xh=x+y10   ...1

∵ ΔCQP~ΔCAB

⇒yh=x+y15   ....2

Adding 1 & 2, we get

x+yh=x+y110+115

⇒ h=6.

Asked in: JEE Main 2020 (04 Sep Shift 1)

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