Two towers A and B , each of height 20   m are situated a distance 200   m apart. A body thrown…

Two towers A and B, each of height 20 m are situated a distance 200 m apart. A body thrown horizontally from the top of the tower A with a velocity 20 ms-1 towards the tower B hits the ground at point P and another body thrown horizontally from the top of tower B with a velocity 30 ms-1 towards the tower A hits the ground at point Q. If a car starting from rest from P reaches Q in 10 seconds, the acceleration of the car is _________ (Acceleration due to gravity =10 ms-2)
  1. 1 ms-2
  2. 2 ms-2
  3. 3 ms-2
  4. 4 ms-2

Solution

The time taken by both the ball to reach the ground is same because initial vertical velocity and height of the tower is the same in each case,

AP=20×2hg=20×4010=40 mQB=20×2hg=30×4010=60 m

PQ=200-100=ut+12at2=0+12×a100100=50aa=2 m s-2

Asked in: AP EAMCET 2018 (25 Apr Shift 1)

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