Two surfaces $A$ and $B$ are enclosing the charges as shown below. The total normal electric induction (T.N…
Two surfaces $A$ and $B$ are enclosing the charges as shown below. The total normal electric induction (T.N.E.I) through the surfaces A and B are respectively.
$+2 q$ and $+2 q$
$+q$ and $+3 q$
$+q$ and $+2 q$
$+2 q$ and $+3 q$
Solution
Total normal electric induction is given by,
$\begin{array}{ll}
& \text { T.N.E.I. }=\sum q_{\text {enclosed }} \\
\therefore \quad & \text { T.N.E.I. for } A=(+2 q-q)=+q \\
& \text { T.N.E.I. for } B=(+3 q-q)=+2 q
\end{array}$
