Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in radius r 2 and the…

Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in radius r2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the tangential speed of the heavier stone. They are reported to experience the same centripetal force. The value of n is, 

  1. 3
  2. 4
  3. 1
  4. 2

Solution

Fcplight=Fcpheavy
So, equating the centripetal forces, 
mv12r=2mv22r2
So, v1=2v2

Asked in: NEET 2015 (Phase 2)

Practice more Motion In Two Dimensions questions on Aicharya