Two stones of masses $\mathrm{m}$ and $3 \mathrm{~m}$ are whirled in horizontal circles, the heavier one in…

Two stones of masses $\mathrm{m}$ and $3 \mathrm{~m}$ are whirled in horizontal circles, the heavier one in radius $\left(\frac{\mathrm{r}}{3}\right)$ and lighter one in radius ' $\mathrm{r}^{\prime}$. The tangential speed of lighter stone is 'n' times that of the value of heavier stone, when they experience same centripetal force. The value of $\mathrm{n}$ is
  1. 2
  2. 3
  3. 1
  4. 4

Solution

Centripetal force $=\frac{\mathrm{mV}_{1}^{2}}{\mathrm{r}}=\frac{3 \mathrm{mV}_{2}^{2}}{\left(\frac{\mathrm{r}}{3}\right)}$ $\begin{aligned} \frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}^{2}} &=9 \\ \frac{\mathrm{V}_{1}}{\mathrm{~V}_{2}^{2}} &=3 \end{aligned}$

Asked in: MHT CET 2020 (14 Oct Shift 1)

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