Two stars ' $\mathrm{P}$ ' and ' $\mathrm{Q}$ ' emit yellow and blue light respectively. The relation…

Two stars ' $\mathrm{P}$ ' and ' $\mathrm{Q}$ ' emit yellow and blue light respectively. The relation between their temperatures $\left(\mathrm{T}_{\mathrm{P}}\right.$ and $\left.\mathrm{T}_{\mathrm{Q}}\right)$ is
  1. $\mathrm{T}_{\mathrm{P}}=\mathrm{T}_{\mathrm{Q}}$
  2. $\mathrm{T}_{\mathrm{P}}=\frac{\mathrm{T}_{\mathrm{Q}}}{2}$
  3. $\mathrm{T}_{\mathrm{P}}>\mathrm{T}_{\mathrm{Q}}$
  4. $\mathrm{T}_{\mathrm{P}} < \mathrm{T}_{\mathrm{Q}}$

Solution

According to wien's law, $\lambda T=$ constant $\therefore \mathrm{T} \propto \frac{1}{\lambda}$ wavelength of blue light is less that than of yellow light. Hence, temperature of $\mathrm{Q}$ is greater than temperature of $\mathrm{P}$.

Asked in: MHT CET 2021 (20 Sep Shift 1)

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