Two springs of spring constants ' $\mathrm{K}^{\prime}$ and ' $2 \mathrm{~K}^{\prime}$ are stretched by same…
Two springs of spring constants ' $\mathrm{K}^{\prime}$ and ' $2 \mathrm{~K}^{\prime}$ are stretched by same force. If ' $\mathrm{w}_{1}{ }^{\circ}$
and ' $\mathrm{w}_{2}$ ' are the energies stored in them respectively then
$\mathrm{w}_{1}=2 \mathrm{w}_{2}$
$\mathrm{w}_{1}=\frac{\mathrm{w}_{2}}{4}$
$\mathrm{w}_{2}=2 \mathrm{w}_{1}$
$\mathrm{w}_{1}=\mathrm{w}_{2}$
Solution
Energy stored in spring of
$w_{1}=\frac{1}{2} k x^{2} \text { constant } k$
Th spring of contant 2k
$w_{2}=\frac{1}{2} (2k) x^{2} \text { constant } k$
So, $w_{2}=2w_{1}$