Two spheres $\mathrm{S}_1$ and $\mathrm{S}_2$ have same radii but temperatures $T_1$ and $T_2$ respectively.…

Two spheres $\mathrm{S}_1$ and $\mathrm{S}_2$ have same radii but temperatures $T_1$ and $T_2$ respectively. Their emissive power is same and emissivity in the ratio 1:4. Then the ratio $T_1: T_2$ is
  1. $2: 1$
  2. $\sqrt{2}: 1$
  3. $1: \sqrt{2}$
  4. $1: 2$

Solution

Given: $\frac{\mathrm{Q}_1}{\mathrm{~A}_1 \mathrm{t}}=\frac{\mathrm{Q}_2}{\mathrm{~A}_2 \mathrm{t}}$ But $A_1=A_2$ as radii are same $\begin{array}{ll} \therefore & \mathrm{Q}_1=\mathrm{Q}_2 \\ \therefore & \mathrm{e}_1 \sigma \mathrm{AT}_1^4=\mathrm{e}_2 \sigma \mathrm{AT}_2^4 \\ \therefore & \frac{\mathrm{~T}_1^4}{\mathrm{~T}_2^4}=\frac{\mathrm{e}_2}{\mathrm{e}_1}=\frac{4}{1} \\ \therefore & \frac{\mathrm{~T}_1}{\mathrm{~T}_2}=\left(\frac{4}{1}\right)^{\frac{1}{4}}=\frac{\sqrt{2}}{1} \end{array}$

Asked in: MHT CET 2024 (11 May Shift 1)

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