Two sources of light emit with a power of 200 W . The ratio of number of photons of visible light emitted by…

Two sources of light emit with a power of 200 W. The ratio of number of photons of visible light emitted by each source having wavelengths 300 nm and 500 nm respectively, will be :
  1. 1:5
  2. 1:3
  3. 5:3
  4. 3:5

Solution

Let n1 and n2 be the number of photons coming out from the first and the second source of light respectively per second.

So, for the first source,

n1×hcλ1=200   ...1

And, for the second source,

n2×hcλ2=200   ...2

From equations (1) and (2), it implies that

n1n2=λ1λ2=300500n1n2=35

Asked in: JEE Main 2024 (29 Jan Shift 2)

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