Two sound waves having wavelengths $5.0 \mathrm{~m}$ and $5.5 \mathrm{~m}$ propagates in a gas with velocity $300 \mathrm{~m} / \mathrm{s}$. The number of beats produced per second is

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Aicharya · Accepted Answer

$\begin{aligned} & \lambda_1=5.0 \mathrm{~m} 	ext { and } \lambda_2=5.5 \mathrm{~m}, \mathrm{v}=300 \mathrm{~m} / \mathrm{s} \ & \mathrm{n}_1=\frac{\mathrm{V}}{\lambda_1}=\frac{300}{5}=60 \mathrm{~Hz} \ & \mathrm{n}_2=\frac{\mathrm{V}}{\lambda_2}=\frac{300}{5.5}=54.5 \mathrm{~Hz} \simeq 54 \mathrm{~Hz} \end{aligned}$ Number of beats $=\mathrm{n}_1-\mathrm{n}_2=60-54=6 \mathrm{~Hz}$

Two sound waves having wavelengths $5.0 \mathrm{~m}$ and $5.5 \mathrm{~m}$ propagates in a gas with velocity…

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