Two slits separated by $0.5 \mathrm{~mm}$ are illuminated by light of wavelength $500 \mathrm{~nm}$. The screen is at a distance of $120 \mathrm{~cm}$ from the slits. The phase difference between the interfering waves at a point $3 \mathrm{~mm}$ on the screen from the central bright fringe is ....…

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Two slits separated by $0.5 \mathrm{~mm}$ are illuminated by light of wavelength $500 \mathrm{~nm}$. The screen is at a distance of $120 \mathrm{~cm}$ from the slits. The phase difference between the interfering waves at a point $3 \mathrm{~mm}$ on the screen from the central bright fringe is ........... .

Aicharya · Accepted Answer

Given, $ \begin{aligned} & \mathrm{d}=0.5 	imes 10^{-9} \mathrm{~m} 	ext { and } \gamma=3 	imes 10^{-3} \mathrm{~mm} \ & \lambda=500 	imes 10^{-9} \mathrm{~m} \ & D=120 \mathrm{~cm}=120 	imes 10^{-2} \mathrm{~m} \ & \gamma=\frac{\Delta x D}{d} \end{aligned} $ $ \Delta x=\frac{\gamma d}{D} $ $ \Delta x=\frac{3 	imes 10^{-3} 	imes 0.5 	imes 10^{-3}}{1.2}=\frac{5}{4} 	imes 10^{-6} $ $ \Delta \phi=\frac{2 \pi 	imes 1.25 	imes 10^{-6}}{500 	imes 10^{-9}}=5 \pi $

Two slits separated by $0.5 \mathrm{~mm}$ are illuminated by light of wavelength $500 \mathrm{~nm}$. The…

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