Two simple harmonic motions are represented by $y_1=5[\sin 2 \pi t+\sqrt{3} \cos 2 \pi t]$ and $y_2=5 \sin \left[2 \pi t+\frac{\pi}{4}\right]$. The ratio of their amplitudes is

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Aicharya · Accepted Answer

$\begin{aligned} & 	ext { } \mathrm{y}_1=5[\sin 2 \pi \mathrm{t}+\sqrt{3} \cos 2 \pi \mathrm{t}] \ & \mathrm{y}_2=5 \sin \left[2 \pi \mathrm{t}+\frac{\pi}{4}ight] \end{aligned}$ $	herefore \quad$ Ratio of amplitudes, $\frac{\mathrm{A}_1}{\mathrm{~A}_2}=\frac{5 	imes \sqrt{(1)^2+(\sqrt{3})^2}}{5}=\frac{2}{1}=2: 1$

Two simple harmonic motions are represented by $y_1=5[\sin 2 \pi t+\sqrt{3} \cos 2 \pi t]$ and $y_2=5 \sin…

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