Two sides of a triangle are $7$ and $9$. Third side $x$ satisfies
Two sides of a triangle are $7$ and $9$. Third side $x$ satisfies
- $2 < x < 16$
- $x > 16$
- $x = 7$
- $x = 9$
Solution
$|7-9| < x < 7+9 \Rightarrow 2 < x < 16$.
Asked in: MH-SSC-9
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