Two satellites $A$ and $B$ having ratio of masses $3: 1$ are revolving in circular orbits of radii ' $r$ ' and ' 4 r '. The ratio of total energy of satellites A to that of $B$ is

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Aicharya · Accepted Answer

$\begin{aligned} \frac{E_A}{E_B} & =\frac{M_A}{M_B} 	imes \frac{r_B}{r_A} \quad \ldots\left(E \propto \frac{M}{r}ight) \ & =\frac{3}{1} 	imes \frac{4 r}{r} \ \frac{E_A}{E_B} & =\frac{12}{1}\end{aligned}$

Two satellites $A$ and $B$ having ratio of masses $3: 1$ are revolving in circular orbits of radii ' $r$ '…

Solution