Two satellites 'A' and 'B' of same mass are revolving round the earth at height '2R' and '3R' respectively above the surface of the earth. The ratio of kinetic energies of A to B will be

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Aicharya · Accepted Answer

$\begin{aligned} 	ext { K.E. } &=\frac{1}{2} \frac{\mathrm{GMm}}{\mathrm{r}} \ 	herefore \frac{\mathrm{K}_{1}}{\mathrm{~K}_{2}} &=\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}} \ &=\frac{3 \mathrm{R}+\mathrm{R}}{3 \mathrm{R}+\mathrm{R}}=\frac{4}{3} \end{aligned}$

Two satellites 'A' and 'B' of same mass are revolving round the earth at height '2R' and '3R' respectively…

Solution