Two rings of same mass 'M' and radius 'R' are so placed that their centre is common and their planes are…

Two rings of same mass 'M' and radius 'R' are so placed that their centre is common and their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the centre and perpendicular to any one ring is
  1. $\frac{3 \mathrm{MR}^{2}}{2}$
  2. $\frac{\mathrm{MR}^{2}}{2}$
  3. $\frac{2 \mathrm{MR}^{2}}{3}$
  4. $\mathrm{MR}^{2}$

Solution

$\mathrm{MR}^{2}+\frac{\mathrm{MR}^{2}}{2}=\frac{3 \mathrm{MR}^{2}}{2}$

Asked in: MHT CET 2020 (15 Oct Shift 1)

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