Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and…

Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
  1. $0 \cdot 031 \mathrm{~m}$
  2. $0 \cdot 125 \mathrm{~m}$
  3. $0 \cdot 250 \mathrm{~m}$
  4. $0 \cdot 0625 \mathrm{~m}$

Solution

AS, $\begin{aligned} f &=\frac{v}{\lambda} \quad[v=50 \mathrm{~m} / \mathrm{s}] \\ \therefore \lambda &=\frac{50}{200}=1 / 4 \end{aligned}$ Now, Distance btw two antinode $=1 / 2$ $\begin{array}{l}=1 / 8=0.125 \mathrm{~m}\end{array}$

Asked in: MHT CET 2020 (19 Oct Shift 1)

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