Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and…
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between the two consecutive antinodes is
$0.125 \mathrm{~m}$
$0.150 \mathrm{~m}$
$0.175 \mathrm{~m}$
$0.200 \mathrm{~m}$
Solution
Velocity of wave, $v=f \lambda$
$\therefore \quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{50}{200}=0.25 \mathrm{~m}$
$\therefore \quad$ Dividing the wavelength for antinodes:
$\begin{aligned}
\lambda & =\frac{0.25}{2} \\
& =0.125 \mathrm{~m}
\end{aligned}$